How do you calculate the total inductance in a parallel combination of inductors?

1 / L_total = 1 / Lā + 1 / Lā + 1 / Lā + ... + 1 / L_n

where:

L_total is the total inductance of the parallel combination.

Lā, Lā, Lā, ..., L_n are the individual inductances of the inductors connected in parallel.

If you have only two inductors in parallel (n=2), the formula simplifies to:

1 / L_total = 1 / Lā + 1 / Lā

To find L_total, take the reciprocal of the sum of the reciprocals of the individual inductances:

L_total = 1 / (1 / Lā + 1 / Lā)

If you have more than two inductors in parallel (n > 2), you just need to extend the formula accordingly by adding more terms:

1 / L_total = 1 / Lā + 1 / Lā + 1 / Lā + ... + 1 / L_n

And then calculate L_total as:

L_total = 1 / (1 / Lā + 1 / Lā + 1 / Lā + ... + 1 / L_n)

Remember to use consistent units for inductance (typically henries, H) when performing the calculations.

1 / L_total = 1 / L1 + 1 / L2 + 1 / L3 + ... + 1 / Ln

Where:

L1, L2, L3, ..., Ln are the individual inductances of the inductors connected in parallel.

To find the total inductance (L_total), follow these steps:

Identify the individual inductances of each inductor in the parallel combination (L1, L2, L3, ..., Ln).

Take the reciprocal of each inductance value (1 / L1, 1 / L2, 1 / L3, ..., 1 / Ln).

Add all the reciprocals together.

Take the reciprocal of the sum to find the total inductance:

L_total = 1 / (1 / L1 + 1 / L2 + 1 / L3 + ... + 1 / Ln)

Note that inductance is usually measured in henrys (H), and when calculating the total inductance, ensure that all individual inductance values are in the same units (e.g., henrys).