To calculate the output impedance of a network using Z-parameters (impedance parameters or open-circuit parameters), you need to have a clear understanding of the network topology and the Z-matrix representation of the network.
Z-parameters are used to describe the relationship between the voltage and current at the input and output ports of a linear, multi-port network. For a two-port network, the Z-parameters can be represented as follows:
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[V1] [Z11 Z12] [I1]
[V2] = [Z21 Z22] [I2]
Where:
V1 and V2 are the voltages at the input and output ports, respectively.
I1 and I2 are the currents entering the input and output ports, respectively.
Z11, Z12, Z21, and Z22 are complex numbers that represent the impedance elements of the network.
To calculate the output impedance, follow these steps:
Step 1: Identify the port you want to analyze. In this case, it's the output port (V2 and I2).
Step 2: Set the input of the port to zero (i.e., V1 = 0). This means the input voltage is zero, effectively making the port an open circuit.
Step 3: Calculate the current at the output port (I2) with the input port set to zero. This can be done by solving the following equation:
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[V2] = [Z11 Z12] [I1]
[V2] = [Z21 Z22] [0]
Since V1 = 0, I1 = 0. The equation simplifies to:
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[V2] = [Z21 Z22] [0]
Step 4: The output impedance (Zout) is then given by the ratio of output voltage (V2) to output current (I2):
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Zout = V2 / I2
Since I1 = 0 in this case, the output current (I2) is zero, and the output impedance will be effectively equal to the output voltage (V2).
Remember that the output impedance, like the Z-parameters, will be a complex number with both real and imaginary components.
It's important to note that Z-parameters are only applicable to linear networks, and the calculations should be done with complex numbers or using phasor notation if working with AC signals. Additionally, if you have a different network configuration (e.g., three-port or four-port), the procedure will be similar but will involve additional Z-parameters and equations to solve.