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How is the reactance of a capacitor calculated, and how does it vary with frequency?

1 Answer

The reactance of a capacitor in an AC (alternating current) circuit is calculated using the following formula:

Reactance (Xc) = 1 / (2 * π * f * C)

Where:

Xc is the reactance of the capacitor in ohms (Ω).
π (pi) is a mathematical constant approximately equal to 3.14159.
f is the frequency of the AC signal in hertz (Hz).
C is the capacitance of the capacitor in farads (F).

The reactance of a capacitor is inversely proportional to both the frequency (f) and the capacitance (C). This means that as the frequency increases, the reactance decreases, and as the capacitance increases, the reactance also decreases.

In simpler terms, as the frequency of the AC signal applied to the capacitor increases, the capacitor becomes more "permeable" to the signal, allowing it to pass through more easily. This is why capacitors are often used in AC circuits to block or attenuate lower frequencies while allowing higher frequencies to pass through.

Conversely, at lower frequencies, the reactance of the capacitor becomes larger, and it acts as a barrier to the flow of AC current. This property is utilized in various electronic applications, such as in filters, impedance matching networks, and energy storage circuits.

To summarize:

Higher frequency leads to lower reactance, allowing the AC signal to pass through more easily.
Lower frequency leads to higher reactance, impeding the flow of the AC signal.

It's important to note that reactance, unlike resistance in DC circuits, does not dissipate energy as heat. Instead, it affects the phase relationship between voltage and current in an AC circuit. The phase shift between voltage and current in a capacitor is -90 degrees.
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